Acronym  thawro, J92 
Name  triangular hebesphenorotunda 
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Vertex figure  [(3,5)^{2}], [3,4,3,5], [3^{3},5], [3^{2},4,6] 
General of army  (is itself convex) 
Colonel of regiment  (is itself locally convex) 
Dihedral angles 

Confer 

External links 
At the first view this polyhedron looks odd, a real find. But consider the base hexagon being scaled by τ = (1+sqrt(5))/2, keeping its orientation and remaining coplanar. The lacing edges incident to that hexagon thereby all keep their lengths. Thus that figure would then be described by xfof3oxFf&#xt. The fhexagon incident faces then are golden xxf triangles, respectively xxxf trapeziae. Both are complementary parts of regular pentagons. And in fact, this derived figure is nothing but a triangle face parallel rotunda (i.e. half) of the id.
The right pic shows however how thawro can be obtained directly by means of an expanded kaleidofaceting from ike. And this relation too is why thawro occures not too seldomly as a cell within CRFs.
As abstract polytope thawro is isomorphic to githawro, thereby replacing pentagons by pentagrams.
Incidence matrix according to Dynkin symbol
xfox3oxFx&#xt → height(1,2) = height(3,4) = 1/sqrt(3) = 0.577350 (F=ff=x+f) height(2,3) = sqrt[(3sqrt(5))/6] = 0.356822 ({3}  pseudo (f,x){6}  pseudo dual F{3}  {6}) o...3o...  3 * * *  2 2 0 0 0 0 0 0  1 2 1 0 0 0 0 [(3,5)^{2}] .o..3.o..  * 6 * *  0 1 1 1 1 0 0 0  0 1 1 1 1 0 0 [3,4,3,5] ..o.3..o.  * * 3 *  0 0 0 2 0 2 0 0  0 1 0 0 2 1 0 [3^{3},5] ...o3...o  * * * 6  0 0 0 0 1 1 1 1  0 0 0 1 1 1 1 [3^{2},4,6] +++ x... ....  2 0 0 0  3 * * * * * * *  1 1 0 0 0 0 0 oo..3oo..&#x  1 1 0 0  * 6 * * * * * *  0 1 1 0 0 0 0 .... .x..  0 2 0 0  * * 3 * * * * *  0 0 1 1 0 0 0 .oo.3.oo.&#x  0 1 1 0  * * * 6 * * * *  0 1 0 0 1 0 0 .o.o3.o.o&#x  0 1 0 1  * * * * 6 * * *  0 0 0 1 1 0 0 ..oo3..oo&#x  0 0 1 1  * * * * * 6 * *  0 0 0 0 1 1 0 ...x ....  0 0 0 2  * * * * * * 3 *  0 0 0 0 0 1 1 .... ...x  0 0 0 2  * * * * * * * 3  0 0 0 1 0 0 1 +++ x...3o...  3 0 0 0  3 0 0 0 0 0 0 0  1 * * * * * * xfo. ....&#xt  2 2 1 0  1 2 0 2 0 0 0 0  * 3 * * * * * {5} .... ox..&#x  1 2 0 0  0 2 1 0 0 0 0 0  * * 3 * * * * .... .x.x&#x  0 2 0 2  0 0 1 0 2 0 0 1  * * * 3 * * * {4} .ooo3.ooo&#xt  0 1 1 1  0 0 0 1 1 1 0 0  * * * * 6 * * ..ox ....&#x  0 0 1 2  0 0 0 0 0 2 1 0  * * * * * 3 * ...x3...x  0 0 0 6  0 0 0 0 0 0 3 3  * * * * * * 1 {6}
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