to save some integrating

For my own future reference, in case I lose the bit of paper on which I jotted it.

In a function of period 2π, a unit step discontinuity in the nth derivative at phase α contributes this to the Fourier series:

i (in e-ik(t-α) – i-n eik(t-α)) / (2πkn+1)

I haven’t the skill to prove this for general n, but then I’m unlikely to need it for n>2.

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3 Responses to to save some integrating

  1. Anton says:

    In other words:

    • 0: sin(k(t-α))/πk
    • 1: −cos(k(t-α))/πk2
    • 2: −sin(k(t-α))/πk3
    • 3: cos(k(t-α))/πk4
    • 4: sin(k(t-α))/πk5
    • Anton says:

      Each of these is the derivative of the next, so it appears to be correct by induction. Yet somehow I am not fully confident of my reasoning.

  2. Anton says:

    Did I ever work out the series for n=2? Cases 1 and 0 came up in some of my experiments in curve-fitting (not blogged), but I do not now recall if I had any use for n=2.

    Heh, a chain of tangent thoughts led from that question to a new approach to my stalled font-fitting project.

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