Incidence matrix according to Dynkin symbol

xxx xox3oAo&#xt   → both heights = 1/2
                    where A = (1+sqrt(6))/2 = 1.724745
(trip || (pseudo) inv. A-trip || trip)

o.. o..3o..    & | 12 * | 1  2  2 1 0 | 2 1  2  2  2 1 | 1 2 2 1
.o. .o.3.o.      |  * 6 | 0  0  4 0 1 | 0 0  4  2  2 0 | 0 2 2 1
-----------------+------+-------------+----------------+--------
x.. ... ...    & |  2 0 | 6  *  * * * | 2 0  2  0  0 1 | 1 2 2 0
... x.. ...    & |  2 0 | * 12  * * * | 1 1  0  1  0 0 | 1 1 0 1
oo. oo.3oo.&#x & |  1 1 | *  * 24 * * | 0 0  1  1  1 0 | 0 1 1 1
o.o o.o3o.o&#x   |  2 0 | *  *  * 6 * | 0 0  0  0  2 1 | 0 0 2 1
.x. ... ...      |  0 2 | *  *  * * 3 | 0 0  4  0  0 0 | 0 2 2 0
-----------------+------+-------------+----------------+--------
x.. x.. ...    & |  4 0 | 2  2  0 0 0 | 6 *  *  *  * * | 1 1 0 0  augmentation rims
... x..3o..    & |  3 0 | 0  3  0 0 0 | * 4  *  *  * * | 1 0 0 1
xx. ... ...&#x & |  2 2 | 1  0  2 0 1 | * * 12  *  * * | 0 1 1 0
... xo. ...&#x & |  2 1 | 0  1  2 0 0 | * *  * 12  * * | 0 1 0 1
ooo ooo3ooo&#x   |  2 1 | 0  0  2 1 0 | * *  *  * 12 * | 0 0 1 1
x.x ... ...&#x   |  4 0 | 2  0  0 2 0 | * *  *  *  * 3 | 0 0 2 0  biaugmentation rims
-----------------+------+-------------+----------------+--------
x.. x..3o..    & ♦  6 0 | 3  6  0 0 0 | 3 2  0  0  0 0 | 2 * * *
xx. xo. ...&#x & ♦  4 2 | 2  2  4 0 1 | 1 0  2  2  0 0 | * 6 * *
xxx ... ...&#x   ♦  4 2 | 2  0  4 2 1 | 0 0  2  0  2 1 | * * 6 *
... xox3oAo&#xt  ♦  6 3 | 0  6 12 3 0 | 0 2  0  6  6 0 | * * * 2