As the order 6 square tiling (x4o6o) has radius 1/sqrt(-4) = 0.5 i, it clearly is not hemi-choral within either honeycomb x3x4o6o and o3x4o6o, while those latter two indeed have the same radius. Thence that bollocell x4o6o still can be blended out by an according overlay.

Since the vertex figure of the former is a hexagonal pyramid oq6oo&#h and that of the latter clearly is a hexagonal prism x q6o, the one in here becomes an according bi-apiculated hexagonal prism. Note that this one still is circumscribable, just as generally required for vertex figures of uniform polytopes, and thus moreover is convex. This in turn shows, that the two laminates of toes (from the first honeycomb) and of coes (from the second honeycomb) attach as disjunct laminates (and won't pleat back).

Incidence matrix according to Dynkin symbol

o6o4x3xØo3*c   (N → ∞)

. . . . .    | 2N |  12  2 | 12 12  6 | 12 6
-------------+----+--------+----------+-----
. . x . .    |  2 | 12N  * |  2  1  1 |  2 2
. . . x .    |  2 |   * 2N |  0  6  0 |  6 0
-------------+----+--------+----------+-----
. o4x . .    |  4 |   4  0 | 6N  *  * |  1 1
. . x3x .    |  6 |   3  3 |  * 4N  * |  2 0
. . x . o3*c |  3 |   3  0 |  *  * 4N |  0 2
-------------+----+--------+----------+-----
. o4x3x .    ♦ 24 |  24 12 |  6  8  0 |  N *
. o4x . o3*c ♦ 12 |  24  0 |  6  0  8 |  * N