Acronym  ... 
Name  hyperbolic order 6 square tiling 
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Circumradius  1/sqrt(4) = 0.5 i 
Vertex figure  [4^{6}] 
Dual  o4o6x 
Confer 

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There exists a regular modwrap of this tiling, obtained by identifying every 4th vertex on each hole. Then it allows a representation as infinite regular skew polyhedron, which happens to be a facial subset of the cubical honeycomb.
Incidence matrix according to Dynkin symbol
x4o6o (N → ∞) . . .  2N  6  6 +++ x . .  2  6N  2 +++ x4o .  4  4  3N snubbed forms: s4o6o
o3o4x4*a (N → ∞) . . .  4N  6  3 3 +++ . . x  2  12N  1 1 +++ o . x4*a  4  4  3N * . o4x  4  4  * 3N snubbed forms: o3o4s4*a
xØo3oØx (N → ∞) . . . .  2N  3 3  6 +++ x . . .  2  3N *  2 . . . x  2  * 3N  2 +++ x . . x  4  2 2  3N
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