Both hyperbolic honeycombs o4x6o4o and x x6o4o have the same curvature and both use the same o4x6o (tehat) as some of their bollocells. Thence it still can be blended out by an according overlay. Since the vertex figure of the former is a square prism hh4oo&#q and that of the latter is a square pyramid oh4oo&#q, the one in here becomes the tegum sum of 2 orthogonally arranged, axially-intersecting q-scaled regular hexagons. Thus it clearly is still circumscribable, just as generally required for vertex figures of uniform polytopes, and thus moreover is convex. This in turn shows, that the two laminates of tehats (from the first honeycomb) and of hips (from the second honeycomb) attach as disjunct laminates (and won't pleat back).

Incidence matrix according to Dynkin symbol

xØo4x6o4o   (N,M → ∞)

. . . . . | 3NM |   2    8 |   8   4   8 |   8  4
----------+-----+----------+-------------+-------
x . . . . |   2 | 3NM    * |   4   0   0 |   4  0
. . x . . |   2 |   * 12NM |   1   1   2 |   2  2
----------+-----+----------+-------------+-------
x . x . . |   4 |   2    2 | 6NM   *   * |   2  0
. o4x . . |   4 |   0    4 |   * 3NM   * |   0  2
. . x6o . |   6 |   0    6 |   *   * 4NM |   1  1
----------+-----+----------+-------------+-------
x . x6o . ♦  12 |   6   12 |   6   0   2 | 2NM  *
. o4x6o . ♦  6M |   0  12M |   0  3M  2M |   * 2N