o3o    
q3o   o3o

using edge sizes x = 1 and q = sqrt(2) = 1.414214

Incidence matrix according to Dynkin symbol

qo3oo3oo&#x   → height = 1/sqrt(3) = 0.577350
(q-tet || pt)

o.3o.3o.    | 4 * ♦ 3 1 | 3 3 | 1 3
.o3.o3.o    | * 1 ♦ 0 4 | 0 6 | 0 4
------------+-----+-----+-----+----
q. .. ..    | 2 0 | 6 * | 2 1 | 1 2
oo3oo3oo&#x | 1 1 | * 4 | 0 3 | 0 3
------------+-----+-----+-----+----
q.3o.       | 3 0 | 3 0 | 4 * | 1 1
qo .. ..&#x | 2 1 | 1 2 | * 6 | 0 2
------------+-----+-----+-----+----
q.3o.3o.    ♦ 4 0 | 6 0 | 4 0 | 1 *
qo3oo ..&#x ♦ 3 1 | 3 3 | 1 3 | * 4