Acronym  ... 
Name  hyperbolic bitruncated order 5 dodecahedral tesselation 
Circumradius  sqrt[1sqrt(5)] = 1.798907 i 
Vertex figure 
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Confer 

As can be read from the matrices below, at every edge there are 2 hexagons. Thus we get as pseudo cells something with hexagons only. From the vertex incidence we further read off that this pseudo tiling happens to use 4 hexagons per vertex. From the here truely being used cells (ti) it is deduced, that any straight edge sequence of that seeming x6o4o needs to be modwrapped to pentagonal holes. Therefore those pseudo cells rather are the skew polyhedron x6o4o5 instead.
Incidence matrix according to Dynkin symbol
o5x3x5o (N → ∞) . . . .  30N  2 2  1 4 1  2 2 ++++ . x . .  2  30N *  1 2 0  2 1 . . x .  2  * 30N  0 2 1  1 2 ++++ o5x . .  5  5 0  6N * *  2 0 . x3x .  6  3 3  * 20N *  1 1 . . x5o  5  0 5  * * 6N  0 2 ++++ o5x3x . ♦ 60  60 30  12 20 0  N * . x3x5o ♦ 60  30 60  0 20 12  * N
or . . . .  15N  4  2 4  4 ++++ . x . . &  2  30N  1 2  3 ++++ o5x . . &  5  5  6N *  2 . x3x .  6  6  * 10N  2 ++++ o5x3x . & ♦ 60  90  12 20  N
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