Acronym  ... 
Name  hyperbolic order 7/2 heptagon tiling 
Circumradius  sqrt[(1cos^{2}(π/7))/(34 cos^{2}(π/7))] = 0.873057 i 
Vertex figure  [7^{7}]/2 
Dual  x7/2o7o 
Confer 

This hyperbolic star tiling can be obtained from x3o7o, when 7 triangles each are joined into one heptagon each. Every part of the tiling will be covered thrice: every triangle of that related tiling would be used in 3 heptagons each.
Incidence matrix according to Dynkin symbol
o7/2o7x (N → ∞) . . .  2N  7  7 +++ . . x  2  7N  2 +++ . o7x  7  7  2N
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