Incidence matrix according to Dynkin symbol

ofx4qoo&#xt   → height(1,2) = sqrt[sqrt(5)-1]/2 = 0.555893
                height(2,3) = sqrt[1+sqrt(5)]/2 = 0.899454
(q-{4} || dual pseudo f-{4} || dual {4})

o..4o..     | 4 * * | 2 2 0 0 | 1 1 2 0
.o.4.o.     | * 4 * | 0 2 1 0 | 0 2 1 0
..o4..o     | * * 4 | 0 0 1 2 | 0 2 0 1
------------+-------+---------+--------
... q..     | 2 0 0 | 4 * * * | 1 0 1 0  q
oo.4oo.&#x  | 1 1 0 | * 8 * * | 0 1 1 0
.oo4.oo&#x  | 0 1 1 | * * 4 * | 0 2 0 0
..x ...     | 0 0 2 | * * * 4 | 0 1 0 1
------------+-------+---------+--------
o..4q..     | 4 0 0 | 4 0 0 0 | 1 * * *  q-{4}
ofx ...&#xt | 1 2 2 | 0 2 2 1 | * 4 * *
... qo.&#x  | 2 1 0 | 1 2 0 0 | * * 4 *
..x4..o     | 0 0 4 | 0 0 0 4 | * * * 1